If the 47th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm and having 50 circular divisions, what is its zero error?

Question

If the 47^th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm and having 50 circular divisions, what is it's zero error?

Short/Brief Note

Solution

In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm

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Vernier Callipers

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Q 46 Q 45 Q 47

Chapter 1: Measurements and Experimentation - Exercise 5 [Page 48]

APPEARS IN

Frank Physics Part 1 [English] Class 9 ICSE

Chapter 1 Measurements and Experimentation
Exercise 5 | Q 46 | Page 48

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