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प्रश्न
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उत्तर
In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm
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संबंधित प्रश्न
Explain the terms : Least count of a screw gauge.
How are they determined?
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
State the formula for calculating length if:
Number of vernier scale division coinciding with the main scale and number of division of main scale on the left-hand side of zero of vernier scale is known.
Which part of vernier callipers is used to measure the external diameter of a cylinder?
Which part of vernier callipers is used to measure the internal length of a hollow cylinder?
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.
What is the function of ratchet in the screw gauge?
State the formula for calculating the pitch of screw.
Thickness of a cricket ball is measured by ______.
