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प्रश्न
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उत्तर
In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm
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संबंधित प्रश्न
Name the two scales of a vernier callipers and explain how it is used to measure length correct up to 0.01 cm.
Describe the procedure to measure the diameter of a wire with the help of a screw gauge.
When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
(i) What is the diameter of the wire in cm?
(ii) If the zero error is +0.005 cm, what is the correct diameter?
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
Why is the metre length in terms of the wavelength of light considered more accurate?
What is the backlash error?
Name the measuring employed to measure the thickness of a paper.
What is the least count in the case of the following instrument?
vernier calipers
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
