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प्रश्न
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उत्तर
In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm
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संबंधित प्रश्न
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
When does a vernier callipers has the positive error?
The circular scale of a screw gauge has 50 divisions. Its spindle moves by 2 mm on the sleeve, when given four complete rotations calculate
- pitch
- least count
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
What do you understand by the following term as applied to micrometre screw gauge?
Thimble
What do you understand by the following term as applied to screw gauge?
Zero error
How do you account for positive zero error for calculating the correct diameter of wires?
A measuring cylinder is filled with water up to a level of 30 ml. A solid body is immersed in it so that the level of water rises to 37 ml. Now the solid body is tied with a cork and then immersed in water so that the water level rises to 40 ml. Find the volume of the solid body and the cork.
How will you measure the least count of vernier caliper?
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
