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प्रश्न
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उत्तर
In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm
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संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
Depth of a small bottle
In figure for vernier callipers, calculate the length recorded.
(a) A vernier scale has 20 divisions. It slides over the main scale, whose pitch is 0.5 mm. If the number of divisions on the left hand of the zero of vernier on the main scale is 38 and the 18th vernier scale division coincides with the main scale, calculate the diameter of the sphere, held in the jaws of vernier callipers.
(b) If the vernier has a negative error of 0.04 cm, calculate the corrected radius of the sphere.
Who invented vernier callipers?
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
How the backlash error is avoided?
State whether the following statement is true or false by writing T/F against it.
A metre scale can measure a length of 6.346 cm.
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
