Advertisements
Advertisements
प्रश्न
In figure for vernier callipers, calculate the length recorded.

Advertisements
उत्तर
Main scale divisions of vernier callipers in one centimetre = 10
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/10` cm = 0.1 cm
Least count (L.C.) = `"Pitch"/"No. of divisions on the vernier scale"`
L.C. = `0.1/10` cm = 0.01 cm
Here main scale reading = 7.3 cm
Vernier scale reading (V.S.D.) coinciding with main scale = 5th
Length recorded = Main scale reading + L.C. × V.S.D.
= 7.3 + 0.01 × 5
= 7.3 + 0.05
= 7.35 cm
APPEARS IN
संबंधित प्रश्न
Up to how many decimal places can a common vernier callipers measure the length in cm?
When does a vernier callipers has the positive error?
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
Name the measuring employed to measure the diameter of a pencil.
What is the least count in the case of the following instrument?
Screw gauge
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
