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प्रश्न
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
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उत्तर
Least count (L.C.) = 0.0025 cm
Error = +0.0125 cm
Correction = – (Error)
= – (+0.0125)
= – 0.0125 cm
Main scale reading = 7.55 cm
Vernier scale division (V.S.D.) coinciding with main scale = 12th
Length recorded = Main scale reading + L.C. × V.S.D.
= 7.55 + 0.0025 × 12
= 7.55 + 0.0300
= 7.58 cm
Correct length = Length recorded + Correction
= 7.58 + (−0.0125)
= 7.58 – 0.0125
= 7.5675 cm
= 7.567 cm
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संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
Internal diameter of a mug
Explain the terms : Pitch .
How are they determined?
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
Figure shows the position of vernier scale while measuring the external length of a wooden cylinder.
- What is the length recorded by the main scale?
- Which reading of vernier scale coincides with the main scale?
- Calculate the length.
Define the term pitch.
When does a vernier callipers has the positive error?
State the correction if the positive error is 7 divisions when the least count is 0.01 cm.
What is the backlash error?
The precision of vernier calipers is ______ mm.
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
