Advertisements
Advertisements
प्रश्न
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
Advertisements
उत्तर
Least count (L.C.) = 0.0025 cm
Error = +0.0125 cm
Correction = – (Error)
= – (+0.0125)
= – 0.0125 cm
Main scale reading = 7.55 cm
Vernier scale division (V.S.D.) coinciding with main scale = 12th
Length recorded = Main scale reading + L.C. × V.S.D.
= 7.55 + 0.0025 × 12
= 7.55 + 0.0300
= 7.58 cm
Correct length = Length recorded + Correction
= 7.58 + (−0.0125)
= 7.58 – 0.0125
= 7.5675 cm
= 7.567 cm
APPEARS IN
संबंधित प्रश्न
State the formula for determining least count for a vernier callipers.
State the formula for calculating length if:
Number of vernier scale division coinciding with the main scale and number of division of main scale on the left-hand side of zero of vernier scale is known.
What do you understand by the following term as applied to micrometre screw gauge?
Thimble scale
What is meant by the pitch of a screw gauge? The pitch of a screw is 1 mm.
Find the reading of the instrument shown in the following figure.
The following diagrams (Fig. 5) show the use of a vernier caliper under three different situations. Study the diagrams carefully and note down the vernier readings in each case.
(a) Measuring the diameter of the rod
(b) Measuring Internal diameter of a cavity
(c) Measuring depth of a cavity
Least count of a vernier caliper is ______ cm.
