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प्रश्न
How can the least count of a screw gauge be decreased?
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उत्तर
The least count of a screw gauge can be decreased by
- Decreasing the pitch and
- Increasing the total number of divisions on the circular scale.
APPEARS IN
संबंधित प्रश्न
State the purpose of ratchet in a screw gauge.
In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.
(a) Find the length.
(b) If zero error of vernier callipers is -0.02 cm,
What is the correct length ?
State the formula for calculating length if:
Number of vernier scale division coinciding with the main scale and number of division of main scale on the left-hand side of zero of vernier scale is known.
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
What do you understand by the following term as applied to micrometre screw gauge?
Sleeve cylinder
Explain the term least count of a screw gauge. How are they determined?
In the following figure, the pitch of the screw is 1 mm. Calculate:
(i) the least count of screw gauge and
(ii) the reading represented in the figure.
What is the least count in the case of the following instrument?
Spring balance
