Advertisements
Advertisements
प्रश्न
Explain the terms : Least count of a screw gauge.
How are they determined?
Advertisements
उत्तर
Least count (L.C.) of a screw gauge : The L.C. of a screw gauge is the distance moved by it in rotating the circular scale by one division.
Thus, L.C. = Pitch of the screw gauge/total no. of divisions on its circular scale.
If a screw moves by 1 mm in one rotation and it has 100 divisions on its circular scale, then pitch of screw = 1 mm.
Thus, L.C. = 1 mm / 100 = 0.01 mm = 0.001 cm
APPEARS IN
संबंधित प्रश्न
Name the two scales of a vernier callipers and explain how it is used to measure length correct up to 0.01 cm.
Is it possible to increase the degree of accuracy by mathematical manipulations? Support your answer by an example.
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
The thimble of a screw gauge has 50 divisions for one rotation. The spindle advances 1 mm when the screw is turned through two rotations.
- What is the pitch of the screw?
- What is the least count of screw gauge?
- When the screw gauge is used to measure the diameter of wire the reading on the sleeve is found to be 0.5 mm and reading on thimble is found, 27 divisions. What is the diameter of the wire in centimetres?
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
State whether the following statement is true or false by writing T/F against it.
The least count of a screw gauge can be lowered by increasing the number of divisions on its thimble.
A Vernier calliper reads a main scale reading of 2.3 cm and the 5th division of the Vernier scale coincides with a main scale division. If the least count is 0.01 cm, what is the actual reading?
