Advertisements
Advertisements
प्रश्न
A vernier callipers has its main scale graduated in mm and 10 divisions on its vernier scale are equal in length to 9 mm. When the two jaws are in contact, the zero of the vernier scale is ahead of the zero of the main scale and the 3rd division of the vernier
scale coincides with a main scale division.
Find : (i) The least count and
(ii) The zero error of the vernier callipers.
Advertisements
उत्तर
(i) Value of 1 m.s.d. =1 mm
10 vernier divisions = 9 m.s.d.
L.C. = Value of 1 m.s.d./number of divisions on the vernier scale
= 1 mm/10
= 0.1 mm or 0.01 cm
(ii) On bringing the jaws together, the zero of the vernier scale is ahead of zero of the main scale, the error is positive.
3rd vernier division coincides with a main scale division.
Total no. of vernier divisions = 10
Zero error = +3 × L.C.
= +3 × 0.01 cm
= +0.03 cm
APPEARS IN
संबंधित प्रश्न
The wavelength of light of a particular colour is 5800 Å.
Express it in nanometre.
The size of bacteria is 1 µ. Find the number of bacteria present in 1 m length.
Describe in steps, how would you use a vernier callipers to measure the length of a small rod?
Why is the metre length in terms of the wavelength of light considered more accurate?
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
How do you account for negative zero error, for calculating the correct diameter of wires?
The Wavelength of a particular colour is 5400Å. Express it in nanometer and metre.
State whether the following statement is true or false by writing T/F against it.
The least count of a screw gauge can be lowered by increasing the number of divisions on its thimble.
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
