मराठी

A Boy Uses a Vernier Callipers to Measure the Thickness of His Pencil. He Measures It to Be 1.4 Mm. If the Zero Error of Vernier Callipers is +0.02 Cm, What is the Correct Thickness of the Pencil? - Physics

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प्रश्न

A boy uses a vernier callipers to measure the thickness of his pencil. He measures it to be 1.4 mm. If the zero error of vernier callipers is +0.02 cm, what is the correct thickness of the pencil?

बेरीज
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उत्तर

Thickness of the pencil (observed reading) = 1.4 mm

Zero error = + 0.02 cm = + 0.2 mm

Correct reading = observed reading - zero error (with sign)

 = 1.4 mm - 0.2 mm

 = 1.2 mm

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Vernier Callipers
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पाठ 1: Measurements and Experimentation - Exercise 1 (B) [पृष्ठ २१]

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सेलिना Concise Physics [English] Class 9 ICSE
पाठ 1 Measurements and Experimentation
Exercise 1 (B) | Q 4 | पृष्ठ २१

संबंधित प्रश्‍न

Name the two scales of a vernier callipers and explain how it is used to measure length correct up to 0.01 cm.


Fig., below shows the reading obtained while measuring the diameter of a wire with a screw gauge. The screw advances by 1 division on the main scale when circular head is rotated once.  

Find:
(i) Pitch of the screw gauge,
(ii) Least count of the screw gauge and
(iii) The diameter of the wire.


(a) A vernier scale has 10 divisions. It slides over the main scale, whose pitch is 1.0 mm. If the number of divisions on the left hand of zero of the vernier scale on the main scale is 56 and the 8th vernier scale division coincides with the main scale, calculate the length in centimetres.
(b) If the above instrument has a negative error of 0.07 cm, calculate the corrected length.


The least count of a vernier callipers is 0.01 cm and it has an error of + 0.07 cm. While measuring the radius of a sphere, the main scale reading is 2.90 cm and the 5th vernier scale division coincides with the main scale. Calculate the correct radius.


State the formula for calculating length if:

The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.


A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate

  1. pitch
  2. observed diameter
  3. least count
  4. corrected diameter.

State the formula for calculating the pitch of screw.


In the following figure, the pitch of the screw is 1 mm. Calculate:
(i) the least count of screw gauge and
(ii) the reading represented in the figure.


State whether the following statement is true or false by writing T/F against it.

The metre scale, vernier calipers, and screw gauge are in decreasing order of least count.


What is meant by zero error of a vernier caliper? How is it determined? Draw neat diagrams to explain it. How is it taken into account to get the correct measurement?

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