Advertisements
Advertisements
प्रश्न
In the following figure, the pitch of the screw is 1 mm. Calculate:
(i) the least count of screw gauge and
(ii) the reading represented in the figure.
Advertisements
उत्तर
Screw gauge in the figure
(i) Pitch of the screw = 1 mm
Divisions on circular scale= 100
least count = pitch of the screw/ divisions on the main scale
L.C. = 1/100 = 0.01 mm= 0.001 cm
(ii) LC. = 0.001 cm
the main scale reading = 2 mm= 0.2 cm
from the figure it is clear that base line coincides with the 97th division of the circular scale.
So, circular scale reading= 97 X 0.001 cm = 0.097 cm Hence, reading shown In the figure= 0.2 + 0.097 = 0.297 cm
APPEARS IN
संबंधित प्रश्न
What is meant by zero error of vernier callipers ? How is it determined? Draw neat diagrams to explain it. How is it taken in account to get the correct measurement?
Name the part of the vernier callipers which is used to measure the following
Internal diameter of a mug
A boy uses a vernier callipers to measure the thickness of his pencil. He measures it to be 1.4 mm. If the zero error of vernier callipers is +0.02 cm, what is the correct thickness of the pencil?
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
A micrometre screw gauge has a negative zero error of 8 divisions. While measuring the diameter of a wire the reading on the main scale is 3 divisions and the 24th circular scale division coincides with baseline.
If the number of divisions on the main scale are 20 to a centimetre and circular scale has 50 divisions, calculate
- pitch
- observed diameter.
- least count
- corrected diameter.
For what range of measurement is micrometre screw gauge used?
The level of water in a measuring cylinder is 12.5 ml. When a stone is lowered in it, the volume is 21.0 ml. Find the volume of the stone.
Name the measuring employed to measure the diameter of a pencil.
