Advertisements
Advertisements
प्रश्न
How do you account for negative zero error, for calculating the correct diameter of wires?
Advertisements
उत्तर
If the zero lines marked on a circular scale, is above the reference line of the main scale, then there is a negative error and the correction is positive.
In the figure, there is 96th division on the circular scale which coincides with the reference line.
∴ Correction = + [n − coinciding division of C.S. × L.C.]
where n is the total number of circular scale divisions.
∴ Correction = + [100 – 96] × 0.001 cm
= 0.004 cm
If observed diameter is 0.557 cm, then :
Corrected diameter
= Observed diameter + Correction
= 0. 557 cm + 0.004 cm
= 0.561 cm
APPEARS IN
संबंधित प्रश्न
The wavelength of light is 589 nm. what is its wavelength in Å?
How can the least count of a screw gauge be decreased?
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 10
Which part of vernier callipers is used to measure the internal length of a hollow cylinder?
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
