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प्रश्न
How do you account for negative zero error, for calculating the correct diameter of wires?
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उत्तर
If the zero lines marked on a circular scale, is above the reference line of the main scale, then there is a negative error and the correction is positive.
In the figure, there is 96th division on the circular scale which coincides with the reference line.
∴ Correction = + [n − coinciding division of C.S. × L.C.]
where n is the total number of circular scale divisions.
∴ Correction = + [100 – 96] × 0.001 cm
= 0.004 cm
If observed diameter is 0.557 cm, then :
Corrected diameter
= Observed diameter + Correction
= 0. 557 cm + 0.004 cm
= 0.561 cm
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संबंधित प्रश्न
A screw gauge has a least count 0.001 cm and zero error +0.007 cm. Draw a neat diagram to represent it.
In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.
(a) Find the length.
(b) If zero error of vernier callipers is -0.02 cm,
What is the correct length ?
Define the term least count as applied to a vernier callipers.
What do you understand by the following term as applied to screw gauge?
Negative zero error
What is the least count in the case of the following instrument?
Spring balance
Define the least count of an instrument.
