Advertisements
Advertisements
प्रश्न
How do you account for negative zero error, for calculating the correct diameter of wires?
Advertisements
उत्तर
If the zero lines marked on a circular scale, is above the reference line of the main scale, then there is a negative error and the correction is positive.
In the figure, there is 96th division on the circular scale which coincides with the reference line.
∴ Correction = + [n − coinciding division of C.S. × L.C.]
where n is the total number of circular scale divisions.
∴ Correction = + [100 – 96] × 0.001 cm
= 0.004 cm
If observed diameter is 0.557 cm, then :
Corrected diameter
= Observed diameter + Correction
= 0. 557 cm + 0.004 cm
= 0.561 cm

APPEARS IN
संबंधित प्रश्न
Define the term 'Vernier constant'.
When is a vernier Callipers said to be free from zero error?
What is meant by zero error of vernier callipers ? How is it determined? Draw neat diagrams to explain it. How is it taken in account to get the correct measurement?
Describe in steps, how would you use a vernier callipers to measure the length of a small rod?
Name the measuring employed to measure the diameter of a needle.
State whether the following statement is true or false by writing T/F against it.
A metre scale can measure a length of 6.346 cm.
State whether true or false. If false, correct the statement.
With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
