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प्रश्न
How do you account for negative zero error, for calculating the correct diameter of wires?
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उत्तर
If the zero lines marked on a circular scale, is above the reference line of the main scale, then there is a negative error and the correction is positive.
In the figure, there is 96th division on the circular scale which coincides with the reference line.
∴ Correction = + [n − coinciding division of C.S. × L.C.]
where n is the total number of circular scale divisions.
∴ Correction = + [100 – 96] × 0.001 cm
= 0.004 cm
If observed diameter is 0.557 cm, then :
Corrected diameter
= Observed diameter + Correction
= 0. 557 cm + 0.004 cm
= 0.561 cm
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संबंधित प्रश्न
Draw a neat and labelled diagram of a screw gauge.
Name its main parts and state their functions.
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
What is the need for measuring length with vernier callipers?
State the formula for calculating length if:
Number of vernier scale division coinciding with the main scale and number of division of main scale on the left-hand side of zero of vernier scale is known.
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
What do you understand by the following term as applied to screw gauge?
Positive zero error
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
