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प्रश्न
State the formula for determining least count for a vernier callipers.
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उत्तर
Least count (L.C.) = `"Pitch"/"No. of vernier scale division"`
For example: If the pitch is 0.1 cm and there are ten vernier scale divisions.
Then L.C. = `0.1/10` = 0.01 cm
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संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
Depth of a small bottle
Explain the terms : Pitch .
How are they determined?
What do you mean by zero error of a screw gauge? How is it accounted for?
The least count of a vernier calipers is :
(a) A vernier scale has 20 divisions. It slides over the main scale, whose pitch is 0.5 mm. If the number of divisions on the left hand of the zero of vernier on the main scale is 38 and the 18th vernier scale division coincides with the main scale, calculate the diameter of the sphere, held in the jaws of vernier callipers.
(b) If the vernier has a negative error of 0.04 cm, calculate the corrected radius of the sphere.
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
What do you understand by the following term as applied to micrometre screw gauge?
Thimble
State whether the following statement is true or false by writing T/F against it.
The metre scale, vernier calipers, and screw gauge are in decreasing order of least count.
What is the least count in the case of the following instrument?
Screw gauge
State whether true or false. If false, correct the statement.
With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
