Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
Number of threads = 20
Distance covered in 20 threads = 10 mm
Pitch of the screw gauge = `10/20` = 0.5 mm
No of divisions on circular scale = 50
`"Least count" = "pitch"/"no. of divisions"`
= 0.01 mm
APPEARS IN
संबंधित प्रश्न
The wavelength of light of a particular colour is 5800 Å.
Express it in nanometre.
Describe in steps, how would you use a vernier callipers to measure the length of a small rod?
A vernier callipers has its main scale graduated in mm and 10 divisions on its vernier scale are equal in length to 9 mm. When the two jaws are in contact, the zero of the vernier scale is ahead of the zero of the main scale and the 3rd division of the vernier
scale coincides with a main scale division.
Find : (i) The least count and
(ii) The zero error of the vernier callipers.
The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned through two revolutions.
(i) What is the pitch of the screw gauge?
(ii) What is the least count of the screw gauge?
State the formula for calculating length if:
The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.
State whether the following statement is true or false by writing T/F against it.
The ratchet of a screw gauge is used to measure the depth of a beaker.
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
Least count of a vernier caliper is ______ cm.
