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प्रश्न
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उत्तर
Number of threads = 20
Distance covered in 20 threads = 10 mm
Pitch of the screw gauge = `10/20` = 0.5 mm
No of divisions on circular scale = 50
`"Least count" = "pitch"/"no. of divisions"`
= 0.01 mm
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संबंधित प्रश्न
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
Up to how many decimal places can a common vernier callipers measure the length in cm?
Define the term least count as applied to a vernier callipers.
The circular scale of a screw gauge has 50 divisions. Its spindle moves by 2 mm on the sleeve, when given four complete rotations calculate
- pitch
- least count
State the formula for calculating the least count of screw.
State whether the following statement is true or false by writing T/F against it.
A metre scale can measure a length of 6.346 cm.
State whether the following statement is true or false by writing T/F against it.
The least count of a screw gauge can be lowered by increasing the number of divisions on its thimble.
