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प्रश्न
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उत्तर
Number of threads = 20
Distance covered in 20 threads = 10 mm
Pitch of the screw gauge = `10/20` = 0.5 mm
No of divisions on circular scale = 50
`"Least count" = "pitch"/"no. of divisions"`
= 0.01 mm
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संबंधित प्रश्न
A boy uses a vernier callipers to measure the thickness of his pencil. He measures it to be 1.4 mm. If the zero error of vernier callipers is +0.02 cm, what is the correct thickness of the pencil?
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
The least count of a vernier callipers is 0.01 cm and it has an error of + 0.07 cm. While measuring the radius of a sphere, the main scale reading is 2.90 cm and the 5th vernier scale division coincides with the main scale. Calculate the correct radius.
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
A micrometre screw gauge has a negative zero error of 8 divisions. While measuring the diameter of a wire the reading on the main scale is 3 divisions and the 24th circular scale division coincides with baseline.
If the number of divisions on the main scale are 20 to a centimetre and circular scale has 50 divisions, calculate
- pitch
- observed diameter.
- least count
- corrected diameter.
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
How do you account for negative zero error, for calculating the correct diameter of wires?
How the backlash error is avoided?
How will you find the Zero Error of Vernier Caliper? Explain.
