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प्रश्न
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उत्तर
Pitch of the screw gauge = 0.5mm = 0.05 cm
Circular scale divisions = 100
Least Count of screw gauge = pitch of the gauge/circular scale divisions
= 0.05/100
= 0.0005cm
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संबंधित प्रश्न
Name the two scales of a vernier callipers and explain how it is used to measure length correct up to 0.01 cm.
What do you mean by zero error of a screw gauge? How is it accounted for?
Name the instrument which has the least count
0.1 mm
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
When does a vernier callipers has the positive error?
Define the least count of an instrument.
