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A Screw Has a Pitch Equal to 0.5 Mm. What Should Be the Number of Divisions on Its Head So as to Read Correctly up to 0.001 Mm with Its Help?

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प्रश्न

A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?

योग
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उत्तर

Pitch of the screw gauge = 0.5 mm

L.C. of the screw gauge = 0.001 mm

No. of divisions on circular scale = Pitch / L.C.

 = 0.5 / 0.001

 = 500

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अध्याय 1: Measurement - Exercise 2 [पृष्ठ ३०]

APPEARS IN

फ्रैंक Physics [English] Class 9 ICSE
अध्याय 1 Measurement
Exercise 2 | Q 27 | पृष्ठ ३०
सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 1 Measurements and Experimentation
Exercise 1 (B) | Q 15 | पृष्ठ २१

संबंधित प्रश्न

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How will you measure the least count of vernier caliper?


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