Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
1 MSD = 1 mm
10 VSD = 9 mm
1 VSD =`9/10`mm
Least count = 1 MSD - 1 VSD
=`1/10`MSD
=`1/10` x 1 mm = 0.1 mm
= 0.01 cm
APPEARS IN
संबंधित प्रश्न
A boy uses a vernier callipers to measure the thickness of his pencil. He measures it to be 1.4 mm. If the zero error of vernier callipers is +0.02 cm, what is the correct thickness of the pencil?
Fig., below shows the reading obtained while measuring the diameter of a wire with a screw gauge. The screw advances by 1 division on the main scale when circular head is rotated once.
Find:
(i) Pitch of the screw gauge,
(ii) Least count of the screw gauge and
(iii) The diameter of the wire.
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
Define the term pitch.
The thimble of a screw gauge has 50 divisions for one rotation. The spindle advances 1 mm when the screw is turned through two rotations.
- What is the pitch of the screw?
- What is the least count of screw gauge?
- When the screw gauge is used to measure the diameter of wire the reading on the sleeve is found to be 0.5 mm and reading on thimble is found, 27 divisions. What is the diameter of the wire in centimetres?
What do you understand by the following term as applied to micrometre screw gauge?
Sleeve cylinder
State whether the following statement is true or false by writing T/F against it.
The diameter of a wire can be measured more accurately by using vernier calipers than by a screw gauge.
State whether the following statement is true or false by writing T/F against it.
A metre scale can measure a length of 6.346 cm.
State whether the following statement is true or false by writing T/F against it.
The metre scale, vernier calipers, and screw gauge are in decreasing order of least count.
