हिंदी

Wrapping it around a pencil and measuring the length of turns with the help of a meter scale. Is this approach more accurate than determining the diameter of the wire with the help of a screw gauge?

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प्रश्न

We can find the diameter of a wire by wrapping it around a pencil and measuring the length of turns with the help of a meter scale. Is this approach more accurate than determining the diameter of the wire with the help of a screw gauge?
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उत्तर

No, we cannot measure the diameter of a wire by wrapping it around a pencil because it is not very accurate. We can use a screw gauge for this purpose as it can measure the diameter correct up to 1/100 of a millimeter or even less.
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अध्याय 1: Measurement - Exercise 5 [पृष्ठ ४८]

APPEARS IN

फ्रैंक Physics [English] Class 9 ICSE
अध्याय 1 Measurement
Exercise 5 | Q 47 | पृष्ठ ४८

संबंधित प्रश्न

Name the part of the vernier callipers which is used to measure the following

External diameter of a tube


A vernier callipers has its main scale graduated in mm and 10 divisions on its vernier scale are equal in length to 9 mm. When the two jaws are in contact, the zero of the vernier scale is ahead of the zero of the main scale and the 3rd division of the vernier

scale coincides with a main scale division.

Find : (i) The least count and

         (ii) The zero error of the vernier callipers.


In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.

(a) Find the length.

(b) If zero error of vernier callipers is -0.02 cm,

What is the correct length ?


A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find

(i) The pitch,

(ii) The least count and

(iii) The zero error of the screw gauge


A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?


The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 10


Find the volume of a book of length 25 cm, breadth 18 cm and height 2 cm in m3.


What do you mean by the term pitch of a screw gauge?

How does the presentation of data in a tabular form help us in analyzing them? Explain with one example.

A Vernier calliper reads a main scale reading of 2.3 cm and the 5th division of the Vernier scale coincides with a main scale division. If the least count is 0.01 cm, what is the actual reading?


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