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प्रश्न
The following figure shows the reading of a vernier caliper used for measuring the thickness of a metal sheet.
(i) Find the least count of the instrument.
(ii) Calculate the thickness of the metal sheet.
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उत्तर
(i) 1 MSD = 1 mm
10 VSD = 9 mm
1 VSD = `9/10` mm
Least count = 1 MSD - 1 VSD
=`1/10` MSD
= `1/10xx1`mm = 0.1 mm = 0.01 cm
(ii) Thickness of the metal sheet
Main scale reading = 3.9 cm
Vernier scale division coinciding with main scale = 8
Vernier scale reading = 8 x 0.01 cm = 0.08 cm
Thickness of the metal sheet = 3.9 + 0.08 = 3.98 cm
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संबंधित प्रश्न
Draw a neat and labelled diagram of a vernier callipers. Name its main parts and state their functions.
Explain the terms : Least count of a screw gauge.
How are they determined?
Fig., below shows the reading obtained while measuring the diameter of a wire with a screw gauge. The screw advances by 1 division on the main scale when circular head is rotated once.
Find:
(i) Pitch of the screw gauge,
(ii) Least count of the screw gauge and
(iii) The diameter of the wire.
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
In figure for vernier callipers, calculate the length recorded.
(a) A vernier scale has 20 divisions. It slides over the main scale, whose pitch is 0.5 mm. If the number of divisions on the left hand of the zero of vernier on the main scale is 38 and the 18th vernier scale division coincides with the main scale, calculate the diameter of the sphere, held in the jaws of vernier callipers.
(b) If the vernier has a negative error of 0.04 cm, calculate the corrected radius of the sphere.
Explain the term least count of a screw gauge. How are they determined?
What is the least count in the case of the following instrument?
vernier calipers
What is the zero error of a screw gauge?
Least count of a vernier caliper is ______ cm.
