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प्रश्न
The wavelength of light of a particular colour is 5800 Å.
Express it in metre.
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उत्तर
As we know, 1 m = 1010 Å
Given, Wavelength of light = 5800 Å
Substituting the value of wavelength in the relation above, we get,
1010 Å = 1 m
1 Å = 10-10 m
∴ 5800 Å = 5800 × 10-10 m
∴ 5800 Å = 5.8 × 10-7 m
Hence, wavelength of 5800 Å in m = 5.8 × 10 -7m.
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संबंधित प्रश्न
When is a vernier Callipers said to be free from zero error?
What is meant by zero error of vernier callipers ? How is it determined? Draw neat diagrams to explain it. How is it taken in account to get the correct measurement?
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
Define metre according to the old definition.
The main scale of vernier callipers has 10 divisions in a centimetre and 10 vernier scale divisions coincide with 9 main scale divisions. Calculate
- pitch
- L.C. of vernier callipers.
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
(a) A vernier scale has 10 divisions. It slides over the main scale, whose pitch is 1.0 mm. If the number of divisions on the left hand of zero of the vernier scale on the main scale is 56 and the 8th vernier scale division coincides with the main scale, calculate the length in centimetres.
(b) If the above instrument has a negative error of 0.07 cm, calculate the corrected length.
State the formula for determining least count for a vernier callipers.
State the correction if the negative error is 7 divisions when the least count is 0.01 cm.
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.

