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प्रश्न
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.

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उत्तर

Here, zero of the vernier scale lies on the right of the zero of the main scale.
Also, the 5th vernier division is coinciding with some main scale division
Thus, zero error = 0 + 5 x L.C. = 0.05 cm
Hence zero correction = -0.05 cm
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संबंधित प्रश्न
Draw a neat and labelled diagram of a vernier callipers. Name its main parts and state their functions.
Explain the terms : Pitch .
How are they determined?
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
Fig., below shows the reading obtained while measuring the diameter of a wire with a screw gauge. The screw advances by 1 division on the main scale when circular head is rotated once.
Find:
(i) Pitch of the screw gauge,
(ii) Least count of the screw gauge and
(iii) The diameter of the wire.
State the correction if the positive error is 7 divisions when the least count is 0.01 cm.
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.

A micrometre screw gauge has a positive zero error of 7 divisions, such that its main scale is marked in 1/2 mm and the circular scale has 100 divisions. The spindle of the screw advances by 1 division complete rotation.
If this screw gauge reading is 9 divisions on the main scale and 67 divisions on the circular scale for the diameter of a thin wire, calculate
- Pitch
- L.C.
- Observed diameter
- Corrected diameter
What do you understand by the following term as applied to micrometre screw gauge?
Thimble
What is the least count in the case of the following instrument?
Stopwatch
