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प्रश्न
The main scale of vernier callipers has 10 divisions in a centimetre and 10 vernier scale divisions coincide with 9 main scale divisions. Calculate
- pitch
- L.C. of vernier callipers.
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उत्तर
Main scale divisions of vernier callipers in one centimetre = 10
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/10` cm
= 0.1 cm
Least count = `"Pitch"/"No. of vernier scale divisions"`
= `0.1/10` cm
= 0.01 cm
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संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
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The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned through two revolutions.
(i) What is the pitch of the screw gauge?
(ii) What is the least count of the screw gauge?
Is it possible to increase the degree of accuracy by mathematical manipulations? Support your answer by an example.
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
State the formula for determining least count for a vernier callipers.
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
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A micrometre screw gauge has a negative zero error of 8 divisions. While measuring the diameter of a wire the reading on the main scale is 3 divisions and the 24th circular scale division coincides with baseline.
If the number of divisions on the main scale are 20 to a centimetre and circular scale has 50 divisions, calculate
- pitch
- observed diameter.
- least count
- corrected diameter.
State whether the following statement is true or false by writing T/F against it.
The diameter of a wire can be measured more accurately by using vernier calipers than by a screw gauge.
