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प्रश्न
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उत्तर
1 MSD = 1 mm
10 VSD = 9 mm
1 VSD =`9/10`mm
Least count = 1 MSD - 1 VSD
=`1/10`MSD
=`1/10` x 1 mm = 0.1 mm
= 0.01 cm
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संबंधित प्रश्न
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
A micrometre screw gauge having a positive zero error of 5 divisions is used to measure diameter of a wire, when reading on the main scale is 3rd division and the 48th circular scale division coincides with baseline. If the micrometer has 10 divisions to a centimetre on the main scale and 100 divisions on a circular scale, calculate
- Pitch of screw
- Least count of screw
- Observed diameter
- Corrected diameter.
What do you understand by the following term as applied to screw gauge?
Negative zero error
Define the least count of an instrument.
How will you measure the least count of vernier caliper?
In a vernier calliper, (N + 1) divisions of the vernier scale coincide with N divisions of the main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
