Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
Pitch of the screw= 0.5 mm
No. of divisions on circular scale = 50
`"Least count"="pitch of the screw"/"no. of divisions on the circular scale"`
so, L.C. = `0.5/50=0.01` mm
APPEARS IN
संबंधित प्रश्न
The size of bacteria is 1 µ. Find the number of bacteria present in 1 m length.
Define the term 'Vernier constant'.
The diameter of a thin wire can be measured by
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
For what range of measurement is micrometre screw gauge used?
Name the measuring employed to measure the diameter of a needle.
State whether the following statement is true or false by writing T/F against it.
The least count of a screw gauge can be lowered by increasing the number of divisions on its thimble.
