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प्रश्न
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उत्तर
Pitch of the screw= 0.5 mm
No. of divisions on circular scale = 50
`"Least count"="pitch of the screw"/"no. of divisions on the circular scale"`
so, L.C. = `0.5/50=0.01` mm
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संबंधित प्रश्न
State three uses of the vernier callipers.
The least count of a vernier calipers is :
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
Is it possible to increase the degree of accuracy by mathematical manipulations? Support your answer by an example.
State the formula for determining least count for a vernier callipers.
State the formula for calculating length if:
The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.
How do you account for positive zero error for calculating the correct diameter of wires?
What is the backlash error?
Thickness of a cricket ball is measured by ______.
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
