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प्रश्न
A screw gauge has 50 divisions on its circular scale and the pitch of the screw is 0.5 mm. What us its least count?
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उत्तर
Pitch of the screw= 0.5 mm
No. of divisions on circular scale = 50
`"Least count"="pitch of the screw"/"no. of divisions on the circular scale"`
so, L.C. = `0.5/50=0.01` mm
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