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A screw gauge has 50 divisions on its circular scale and the pitch of the screw is 0.5 mm. What us its least count?

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Question

A screw gauge has 50 divisions on its circular scale and the pitch of the screw is 0.5 mm. What us its least count?
Short/Brief Note
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Solution

Pitch of the screw= 0.5 mm

No. of divisions on circular scale = 50

`"Least count"="pitch of the screw"/"no. of divisions on the circular scale"`

so, L.C. = `0.5/50=0.01` mm

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Chapter 1: Measurement - Exercise 5 [Page 47]

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Frank Physics [English] Class 9 ICSE
Chapter 1 Measurement
Exercise 5 | Q 42 | Page 47

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