Advertisements
Advertisements
Question
While measuring the length of a rod with a vernier callipers, below shows the position of its scales. What is the length of the rod?
Advertisements
Solution
L.C. of vernier callipers = 0.01 cm
In the shown scale,
Main scale reading = 3.3 cm
The 6th vernier division coincides with an m.s.d.
Therefore, vernier scale reading = 6 × 0.01 cm = 0.06 cm
Total reading = M.S.R. + V.S.R.
= 3.3 + 0.06
= 3.36 cm
RELATED QUESTIONS
Describe the procedure to measure the diameter of a wire with the help of a screw gauge.
The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned through two revolutions.
(i) What is the pitch of the screw gauge?
(ii) What is the least count of the screw gauge?
In figure for vernier callipers, calculate the length recorded.
The least count of a vernier callipers is 0.01 cm and it has an error of + 0.07 cm. While measuring the radius of a sphere, the main scale reading is 2.90 cm and the 5th vernier scale division coincides with the main scale. Calculate the correct radius.
Explain the term least count of a screw gauge. How are they determined?
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
State whether true or false. If false, correct the statement.
With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
