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प्रश्न
While measuring the length of a rod with a vernier callipers, below shows the position of its scales. What is the length of the rod?

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उत्तर
L.C. of vernier callipers = 0.01 cm
In the shown scale,
Main scale reading = 3.3 cm
The 6th vernier division coincides with an m.s.d.
Therefore, vernier scale reading = 6 × 0.01 cm = 0.06 cm
Total reading = M.S.R. + V.S.R.
= 3.3 + 0.06
= 3.36 cm
संबंधित प्रश्न
Define the term 'Vernier constant'.
When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
(i) What is the diameter of the wire in cm?
(ii) If the zero error is +0.005 cm, what is the correct diameter?
When does a vernier callipers has the negative error?
State the correction if the positive error is 7 divisions when the least count is 0.01 cm.
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.

Find the volume of a book of length 25 cm, breadth 18 cm and height 2 cm in m3.
The following diagrams (Fig. 5) show the use of a vernier caliper under three different situations. Study the diagrams carefully and note down the vernier readings in each case.

(a) Measuring the diameter of the rod

(b) Measuring Internal diameter of a cavity

(c) Measuring depth of a cavity
