Advertisements
Advertisements
प्रश्न
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
Advertisements
उत्तर
Pitch of a screw gauge = 0.5 mm
No. of divisions on the circular scale = 100
L.C. = `(0.5/100)` mm
= 0.005 mm or 0.0005 cm
APPEARS IN
संबंधित प्रश्न
Define the term least count as applied to a vernier callipers.
A micrometre screw gauge having a positive zero error of 5 divisions is used to measure diameter of a wire, when reading on the main scale is 3rd division and the 48th circular scale division coincides with baseline. If the micrometer has 10 divisions to a centimetre on the main scale and 100 divisions on a circular scale, calculate
- Pitch of screw
- Least count of screw
- Observed diameter
- Corrected diameter.
How the backlash error is avoided?
What is the least count in the case of the following instrument?
vernier calipers
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
