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प्रश्न
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
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उत्तर
Pitch of a screw gauge = 0.5 mm
No. of divisions on the circular scale = 100
L.C. = `(0.5/100)` mm
= 0.005 mm or 0.0005 cm
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संबंधित प्रश्न
Draw a neat and labelled diagram of a screw gauge.
Name its main parts and state their functions.
A vernier callipers has its main scale graduated in mm and 10 divisions on its vernier scale are equal in length to 9 mm. When the two jaws are in contact, the zero of the vernier scale is ahead of the zero of the main scale and the 3rd division of the vernier
scale coincides with a main scale division.
Find : (i) The least count and
(ii) The zero error of the vernier callipers.
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
State the formula for calculating length if:
The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.
A measuring cylinder is filled with water up to a level of 30 ml. A solid body is immersed in it so that the level of water rises to 37 ml. Now the solid body is tied with a cork and then immersed in water so that the water level rises to 40 ml. Find the volume of the solid body and the cork.
Define the least count of an instrument.
