Advertisements
Advertisements
प्रश्न
The wavelength of light of a particular colour is 5800 Å.
Express it in nanometre.
Advertisements
उत्तर
As we know, 1 nm = 10 Å
Given, Wavelength of light of particular colour = 5800 Å
Substituting the value of wavelength in the relation above, we get,
10 Å = 1 nm
1 Å = `1/10` nm
∴ 5800 Å = `1/10` × 5800 nm
∴ 5800 Å = 580 nm
Hence, wavelength of 5800 Å in nm = 580 nm.
APPEARS IN
संबंधित प्रश्न
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
The main scale of vernier callipers has 10 divisions in a centimetre and 10 vernier scale divisions coincide with 9 main scale divisions. Calculate
- pitch
- L.C. of vernier callipers.
When does a vernier callipers has the negative error?
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.

What is the function of ratchet in the screw gauge?
The Wavelength of a particular colour is 5400Å. Express it in nanometer and metre.
The following diagrams (Fig. 5) show the use of a vernier caliper under three different situations. Study the diagrams carefully and note down the vernier readings in each case.

(a) Measuring the diameter of the rod

(b) Measuring Internal diameter of a cavity

(c) Measuring depth of a cavity
A Vernier calliper reads a main scale reading of 2.3 cm and the 5th division of the Vernier scale coincides with a main scale division. If the least count is 0.01 cm, what is the actual reading?
