हिंदी

The level of water in a measuring cylinder is 12.5 ml. When a stone is lowered in it, the volume is 21.0 ml. Find the volume of the stone. - Physics

Advertisements
Advertisements

प्रश्न

The level of water in a measuring cylinder is 12.5 ml. When a stone is lowered in it, the volume is 21.0 ml. Find the volume of the stone.

संख्यात्मक
Advertisements

उत्तर

Level of water in measuring cylinder = V1 = 12.5 ml
When a stone is lowered, then the level of water in measuring cylinder
= V2 = 21.0 ml
Volume of stone = V2 − V1
V = 21.0 − 12.5
V = 8.5 ml

shaalaa.com
Vernier Callipers
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Measurements and Experimentation - Unit 5 Exercise 5

APPEARS IN

गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
अध्याय 1 Measurements and Experimentation
Unit 5 Exercise 5 | Q 7

संबंधित प्रश्न

Define the term 'Vernier constant'.


Name the part of the vernier callipers which is used to measure the following

External diameter of a tube


Draw a neat and labelled diagram of a screw gauge.

Name its main parts and state their functions.


A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find

(i) The pitch,

(ii) The least count and

(iii) The zero error of the screw gauge


Figure shows the position of vernier scale while measuring the external length of a wooden cylinder.

  1. What is the length recorded by the main scale?
  2. Which reading of vernier scale coincides with the main scale?
  3. Calculate the length.

A micrometre screw gauge has a negative zero error of 8 divisions. While measuring the diameter of a wire the reading on the main scale is 3 divisions and the 24th circular scale division coincides with baseline.
If the number of divisions on the main scale are 20 to a centimetre and circular scale has 50 divisions, calculate

  1. pitch
  2. observed diameter.
  3. least count
  4. corrected diameter.

What do you understand by the following term as applied to micrometre screw gauge?

Sleeve scale


Define the pitch of the screw gauge.

Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.


If the 47th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm and having 50 circular divisions, what is it's zero error?

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×