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प्रश्न
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उत्तर
The presentation of the data in a tabular form helps in quickly grasping and analyzing the recorded observations. For example, to measure a diameter using a vernier caliper we record the following data in a tabular form as follows
Vernier caliper
| No. of observations | Main scale reading (cm) | No. of vernier divisions p coinciding with main scale | Vernier reading =L.C. X p (cm) | Observed diameter |
| 1 | ||||
| 2 | ||||
| 3 |
The measurements corresponding to one physical quantity from one instrument must be recorded in one table. And the name of the instrument should be written on top. Observation must be recorded up to the limit of the instrument and form the recorded individual observations, calculate the mean value, and record it at the bottom of the column.
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संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
Internal diameter of a mug
Explain the terms : Least count of a screw gauge.
How are they determined?
In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.
(a) Find the length.
(b) If zero error of vernier callipers is -0.02 cm,
What is the correct length ?
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
Is it possible to increase the degree of accuracy by mathematical manipulations? Support your answer by an example.
State the correction if the positive error is 7 divisions when the least count is 0.01 cm.
A micrometre screw gauge has a positive zero error of 7 divisions, such that its main scale is marked in 1/2 mm and the circular scale has 100 divisions. The spindle of the screw advances by 1 division complete rotation.
If this screw gauge reading is 9 divisions on the main scale and 67 divisions on the circular scale for the diameter of a thin wire, calculate
- Pitch
- L.C.
- Observed diameter
- Corrected diameter
What do you understand by the following term as applied to screw gauge?
Zero error
Explain the term least count of a screw gauge. How are they determined?
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
