Advertisements
Advertisements
प्रश्न
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
Advertisements
उत्तर
Pitch of the screw gauge = 0.5 mm
L.C. of the screw gauge = 0.001 mm
No. of divisions on circular scale = Pitch / L.C.
= 0.5 / 0.001
= 500
संबंधित प्रश्न
The wavelength of light of a particular colour is 5800 Å.
Express it in nanometre.
The diameter of a thin wire can be measured by
While measuring the length of a rod with a vernier callipers, below shows the position of its scales. What is the length of the rod?
The main scale of vernier callipers has 10 divisions in a centimetre and 10 vernier scale divisions coincide with 9 main scale divisions. Calculate
- pitch
- L.C. of vernier callipers.
Up to how many decimal places can a common vernier callipers measure the length in cm?
Which part of vernier callipers is used to measure the external diameter of a cylinder?
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
