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प्रश्न
A screw gauge has a least count 0.001 cm and zero error +0.007 cm. Draw a neat diagram to represent it.
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उत्तर
Diagram of a screw gauge with L.C. 0.001 cm and zero error +0.007 cm.
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संबंधित प्रश्न
A boy uses a vernier callipers to measure the thickness of his pencil. He measures it to be 1.4 mm. If the zero error of vernier callipers is +0.02 cm, what is the correct thickness of the pencil?
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 10
The main scale of vernier callipers has 10 divisions in a centimetre and 10 vernier scale divisions coincide with 9 main scale divisions. Calculate
- pitch
- L.C. of vernier callipers.
The circular scale of a screw gauge has 50 divisions. Its spindle moves by 2 mm on the sleeve, when given four complete rotations calculate
- pitch
- least count
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
In the following figure, the pitch of the screw is 1 mm. Calculate:
(i) the least count of screw gauge and
(ii) the reading represented in the figure.
State whether the following statement is true or false by writing T/F against it.
A metre scale can measure a length of 6.346 cm.
How will you measure the least count of vernier caliper?
A Vernier calliper reads a main scale reading of 2.3 cm and the 5th division of the Vernier scale coincides with a main scale division. If the least count is 0.01 cm, what is the actual reading?
