How can the least count of a screw gauge be decreased? - Physics

Question

How can the least count of a screw gauge be decreased?

Short/Brief Note

Solution

The least count of a screw gauge can be decreased by

Decreasing the pitch and
Increasing the total number of divisions on the circular scale.

shaalaa.com

Vernier Callipers

Is there an error in this question or solution?

Q 15 Q 14.2 Q 16

Chapter 1: Measurements and Experimentation - Exercise 1 (B) [Page 20]

APPEARS IN

Selina Concise Physics [English] Class 9 ICSE

Chapter 1 Measurements and Experimentation
Exercise 1 (B) | Q 15 | Page 20

RELATED QUESTIONS

In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.

(a) Find the length.

(b) If zero error of vernier callipers is -0.02 cm,

What is the correct length ?

A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find

(i) The pitch,

(ii) The least count and

(iii) The zero error of the screw gauge

Who invented vernier callipers?

State the formula for determining a pitch

What do you understand by the following term as applied to micrometre screw gauge?

Sleeve cylinder

State two limitations of a metre rule.

What is the purpose of a ratchet in a screw gauge?

'Each measuring instrument has a limit of accuracy'. Comment on the statement.

Why is the screw gauge so named?

What is meant by zero error of a vernier caliper? How is it determined? Draw neat diagrams to explain it. How is it taken into account to get the correct measurement?