Advertisements
Advertisements
प्रश्न
In figure for vernier callipers, calculate the length recorded.

Advertisements
उत्तर
Main scale divisions of vernier callipers in one centimetre = 10
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/10` cm = 0.1 cm
Least count (L.C.) = `"Pitch"/"No. of divisions on the vernier scale"`
L.C. = `0.1/10` cm = 0.01 cm
Here main scale reading = 7.3 cm
Vernier scale reading (V.S.D.) coinciding with main scale = 5th
Length recorded = Main scale reading + L.C. × V.S.D.
= 7.3 + 0.01 × 5
= 7.3 + 0.05
= 7.35 cm
APPEARS IN
संबंधित प्रश्न
The wavelength of light is 589 nm. what is its wavelength in Å?
Describe the procedure to measure the diameter of a wire with the help of a screw gauge.
When does a vernier callipers has the positive error?
State the formula for calculating the least count of screw.
Define the least count of an instrument.
The main scale reading while measuring the thickness of a rubber ball using Vernier caliper is 7 cm and the Vernier scale coincidence is 6. Find the radius of the ball.
Least count of a vernier caliper is ______ cm.
A Vernier calliper reads a main scale reading of 2.3 cm and the 5th division of the Vernier scale coincides with a main scale division. If the least count is 0.01 cm, what is the actual reading?
