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When a Screw Gauge with a Least Count of 0.01 Mm is Used to Measure the Diameter of a Wire, the Reading on the Sleeve is Found to Be 1 Mm and the Reading on the Thimble is Found to Be 27

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Question

When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.

(i) What is the diameter of the wire in cm?

(ii) If the zero error is +0.005 cm, what is the correct diameter?

Sum
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Solution

(i) L.C. of screw gauge = 0.01 mm or 0.001 cm

Main scale reading = 1 mm or 0.1 cm

No. of division of circular head in line with the base line (p) = 27

Circular scale reading = (p) × L.C.

 = 27 × 0.001 cm

 = 0.027 cm

Diameter (Total reading) = M.s.r. + circular scale reading

 = (0.1 + 0.027) cm

 = 0.127 cm

(ii) Zero error = 0.005 cm

Correct reading = Observed reading - zero error (with sign)

 = [0.127 - (+0.005)] cm

 = 0.122 cm

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Chapter 1: Measurements and Experimentation - Exercise 1 (B) [Page 21]

APPEARS IN

Selina Concise Physics [English] Class 9 ICSE
Chapter 1 Measurements and Experimentation
Exercise 1 (B) | Q 12 | Page 21

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