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Question
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
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Solution
Time period = Total time/total no. of oscillations
= (5/2) s
= 2.5 s
Let 'l' be the length. Then,
`T = 2pisqrt(l/"g")`
or , `2.5 = 2(3.14)sqrt(l/9.8)`
or , 0.398 = `sqrt(l/9.8)`
or , `l = (0.398)^2(9.8)`
or , l = 1.55 m
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