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Question
If the 4th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm, what is it's zero error?
One Line Answer
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Solution
In this case, the zero error is positive
Least count of screw gauge = 0.01 mm
Thus, zero error = 0 + 4 X L.C. = 0.04 mm
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