हिंदी

Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of wire.

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प्रश्न

Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.

संख्यात्मक
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उत्तर

No. of circular scale divisions = 200
Pitch = 1 mm

Least count (L.C.) = `"Pitch"/"No. of circular divisions"`

= `(1 "mm")/200`

= 0.005 mm

L.C. = 0.0005 cm

Main scale reading = 5 mm = 0.5 cm

(C.S.D.) circular scale reading = 34 divisions

Observed diameter of wire = Main scale reading + L.C. × C.S.D.
= 0.5 + 0.0005 × 34
= 0.5 + 0.0170
= 0.5170 cm

Redius of wire = `"diameter"/2`
= `0.5170/2`
= 0.2585 cm

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अध्याय 1: Measurements and Experimentation - Unit 4 Practice Problems 2

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
अध्याय 1 Measurements and Experimentation
Unit 4 Practice Problems 2 | Q 1

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