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प्रश्न
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
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उत्तर
Number of circular scale divisions = 100
Distance moved by spindle (screw) = 2.5 mm
No. of complete rotations given = 5
(1) Pitch = `"Distance moved by screw on sleeve"/"No. of complete rotations"`
= `2.5/5`
= 0.5 mm
= 0.05 cm
(2) Least count = `"Pitch"/"No. of circular scale divisions"`
= `0.05/100` cm
= 0.0005 cm
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