Advertisements
Advertisements
प्रश्न
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
Advertisements
उत्तर
Number of circular scale divisions = 100
Distance moved by spindle (screw) = 2.5 mm
No. of complete rotations given = 5
(1) Pitch = `"Distance moved by screw on sleeve"/"No. of complete rotations"`
= `2.5/5`
= 0.5 mm
= 0.05 cm
(2) Least count = `"Pitch"/"No. of circular scale divisions"`
= `0.05/100` cm
= 0.0005 cm
APPEARS IN
संबंधित प्रश्न
A screw gauge has a least count 0.001 cm and zero error +0.007 cm. Draw a neat diagram to represent it.
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 100
(a) A vernier scale has 10 divisions. It slides over the main scale, whose pitch is 1.0 mm. If the number of divisions on the left hand of zero of the vernier scale on the main scale is 56 and the 8th vernier scale division coincides with the main scale, calculate the length in centimetres.
(b) If the above instrument has a negative error of 0.07 cm, calculate the corrected length.
How do you account for positive zero error for calculating the correct diameter of wires?
What is meant by the pitch of a screw gauge? The pitch of a screw is 1 mm.
Find the reading of the instrument shown in the following figure.
State whether true or false. If false, correct the statement.
With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
