हिंदी

The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate pitch least count of the screw gauge.

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प्रश्न

The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate

  1. pitch
  2. least count of the screw gauge
संख्यात्मक
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उत्तर

Number of circular scale divisions = 100
Distance moved by spindle (screw) = 2.5 mm
No. of complete rotations given = 5

(1) Pitch = `"Distance moved by screw on sleeve"/"No. of complete rotations"`

= `2.5/5`

= 0.5 mm

= 0.05 cm

(2) Least count = `"Pitch"/"No. of circular scale divisions"`

= `0.05/100` cm

= 0.0005 cm

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अध्याय 1: Measurements and Experimentation - Unit 4 Practice Problems 1

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 9
अध्याय 1 Measurements and Experimentation
Unit 4 Practice Problems 1 | Q 2
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