Advertisements
Advertisements
प्रश्न
The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned through two revolutions.
(i) What is the pitch of the screw gauge?
(ii) What is the least count of the screw gauge?
Advertisements
उत्तर
No. of divisions on the circular scale = 50
(i) Pitch = Distance moved ahead in one revolution
= 1 mm/2 = 0.5 mm
(ii) L.C. = Pitch/No. of divisions on the circular head
= (0.5/50) mm
= 0.01 mm
APPEARS IN
संबंधित प्रश्न
The size of bacteria is 1 µ. Find the number of bacteria present in 1 m length.
(a) A vernier scale has 10 divisions. It slides over the main scale, whose pitch is 1.0 mm. If the number of divisions on the left hand of zero of the vernier scale on the main scale is 56 and the 8th vernier scale division coincides with the main scale, calculate the length in centimetres.
(b) If the above instrument has a negative error of 0.07 cm, calculate the corrected length.
State the formula for calculating length if:
Number of vernier scale division coinciding with the main scale and number of division of main scale on the left-hand side of zero of vernier scale is known.
State the formula for calculating length if:
The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.
What do you understand by the following term as applied to micrometre screw gauge?
Sleeve cylinder
Find the volume of a book of length 25 cm, breadth 18 cm and height 2 cm in m3.
What is the least count in the case of the following instrument?
Spring balance
The main scale reading while measuring the thickness of a rubber ball using Vernier caliper is 7 cm and the Vernier scale coincidence is 6. Find the radius of the ball.
How will you find the Zero Error of Vernier Caliper? Explain.
