Advertisements
Advertisements
Question
The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned through two revolutions.
(i) What is the pitch of the screw gauge?
(ii) What is the least count of the screw gauge?
Advertisements
Solution
No. of divisions on the circular scale = 50
(i) Pitch = Distance moved ahead in one revolution
= 1 mm/2 = 0.5 mm
(ii) L.C. = Pitch/No. of divisions on the circular head
= (0.5/50) mm
= 0.01 mm
APPEARS IN
RELATED QUESTIONS
Define the least count of vernier callipers. How do you determine it?
Define metre according to the old definition.
Define the term pitch.
Define the term least count as applied to a vernier callipers.
How do you account for negative zero error, for calculating the correct diameter of wires?
What is the least count in the case of the following instrument?
Stopwatch
In a vernier calipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
