Advertisements
Advertisements
Question
The following figure shows a manometer containing a liquid of density p. The limb P of the manometer is connected to a vessel V and the limb Q is open to atmosphere. The difference in the levels of liquid in the two limbs of the manometer is h as shown in the diagram. The atmospheric pressure is P0.
(i) What is the pressure on the liquid surface in the limb Q?
(ii) What is the pressure on the liquid surface in the limb P?
Advertisements
Solution
(i) The pressure on the liquid surface in the limb Q is equal to atmospheric pressure i.e P0.
(ii) According to the manometer principle, the difference in atmospheric pressure in two limbs is equal to the difference in height of liquid in two limbs.
So pressure at P = pressure at Q + h × p × g.
P0= PQ + h ×p × g.
APPEARS IN
RELATED QUESTIONS
Consider the equations `P=lim_(triangles->0)"F"/(triangle"S")` and P1 - P2 = pgz. In an elevator accelerating upward
Define one pascal (Pa), the S.I. unit of pressure.
Explain the principle of a hydraulic machine. Name two devices which work on this principle.
In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 cm2. What force is obtained on its piston of area of cross section 100 cm2 ?
Select the correct option.
The pressure exerted by 50 kg (g = 10 m/s−2) on an area of cross-section of 2 m2 is
What is the use of altimeter?
What is the principle of a hydraulic machine?
Match the following:
| 1. | Hydraulic press | a. | Archimedes |
| 2. | Cartesian Diver | b. | Floatation |
| 3. | Hydrostatic Balance | c. | Pascal’s law |
| 4. | Hydrometer | d. | Buoyancy |
A hydraulic press can lift 100 kg when a mass 'm' is placed on the smaller piston. It can lift ______ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.
