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Question
The following figure shows a manometer containing a liquid of density p. The limb P of the manometer is connected to a vessel V and the limb Q is open to atmosphere. The difference in the levels of liquid in the two limbs of the manometer is h as shown in the diagram. The atmospheric pressure is P0.
(i) What is the pressure on the liquid surface in the limb Q?
(ii) What is the pressure on the liquid surface in the limb P?
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Solution
(i) The pressure on the liquid surface in the limb Q is equal to atmospheric pressure i.e P0.
(ii) According to the manometer principle, the difference in atmospheric pressure in two limbs is equal to the difference in height of liquid in two limbs.
So pressure at P = pressure at Q + h × p × g.
P0= PQ + h ×p × g.
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