Advertisements
Advertisements
प्रश्न
The following figure shows a manometer containing a liquid of density p. The limb P of the manometer is connected to a vessel V and the limb Q is open to atmosphere. The difference in the levels of liquid in the two limbs of the manometer is h as shown in the diagram. The atmospheric pressure is P0.
(i) What is the pressure on the liquid surface in the limb Q?
(ii) What is the pressure on the liquid surface in the limb P?
Advertisements
उत्तर
(i) The pressure on the liquid surface in the limb Q is equal to atmospheric pressure i.e P0.
(ii) According to the manometer principle, the difference in atmospheric pressure in two limbs is equal to the difference in height of liquid in two limbs.
So pressure at P = pressure at Q + h × p × g.
P0= PQ + h ×p × g.
APPEARS IN
संबंधित प्रश्न
The areas of pistons in a hydraulic machine are 5 cm2 and 625 cm2. What force on the smaller piston will support a load of 1250 N on the larger piston? State any assumption which you make in your calculation.
What force is applied on a piston of area of cross section 2 cm2 to obtain a force 150 N on the piston of area of cross section 12 cm2 in a hydraulic machine?
The pressure in the water pipe on the ground floor of a building is 40000 pascals, whereas on the first floor it’s 10000 pascals. Find the height of the first floor. (Acceleration due to gravity g = 10 ms−2)
State and explain Pascal's law of transmission of pressure.
Unit of pressure is
Match the following:
| 1. | Hydraulic press | a. | Archimedes |
| 2. | Cartesian Diver | b. | Floatation |
| 3. | Hydrostatic Balance | c. | Pascal’s law |
| 4. | Hydrometer | d. | Buoyancy |
Consider a water tank shown in the figure. It has one wall at x = L and can be taken to be very wide in the z direction. When filled with a liquid of surface tension S and density ρ, the liquid surface makes angle θ(θ << 1) with the x-axis at x = L. If y(x) is the height of the surface then the equation for y(x) is:
(take θ(x) = sin θ(x) = tan θ(x) = `dy/dx`, g is the acceleration due to gravity)
