Advertisements
Advertisements
Question
At a given place, a barometer records 70 cm of Hg. If the mercury in the barometer is replaced by water, what would be resulting in reading? (Density of Hg = 13600 kg/m3; Density of water = 1000 kg/m3)
Advertisements
Solution
Height of mercury column = h = 70 cm = 0.70 m
Density of mercury = ρ= 13600 kg/m3
Acceleration due to gravity = g = 10 m/s2
Pressure = hρg
For water:
Height of water column = h’ =?
Pressure due to water column = P’
Density of water = ρw = 1000 kg/m3
P’ = h’ρwg
But, P’ = P
h’ρwg = hρg
h’ρw = hρ
h’ = `"hρ"/"ρ"_"w"=(0.7xx13600)/1000` = 9.52 m
APPEARS IN
RELATED QUESTIONS
Define one pascal (Pa), the S.I. unit of pressure.
66640 Pa pressure is exerted by 0.50 m vertical column of a liquid. If g = 9.8 Nkg−1, calculate the density of the liquid.
The pressure in the water pipe on the ground floor of a building is 40000 pascals, whereas on the first floor it’s 10000 pascals. Find the height of the first floor. (Acceleration due to gravity g = 10 ms−2)
The following figure shows a manometer containing a liquid of density p. The limb P of the manometer is connected to a vessel V and the limb Q is open to atmosphere. The difference in the levels of liquid in the two limbs of the manometer is h as shown in the diagram. The atmospheric pressure is P0.
(i) What is the pressure on the liquid surface in the limb Q?
(ii) What is the pressure on the liquid surface in the limb P?

State and explain Pascal's law of transmission of pressure.
For what purpose is the acid battery hydrometer used?
Pascal’s law is used in
Analogy
Pascal’s law: ______:: Surface tensin: ______.
