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Question
The combined resistance of a galvanometer of resistance 500Ω and its shunt is 21Ω. Calculate the value of shunt.
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Solution
Here, G = 500Ω and Req = 21Ω
`1/R_(eq)=1/G+1/S`
`therefore 1/S=1/R_(eq)-1/G=(G-R_(eq))/(GxxR_(eq)`
`therefore S=(GxxR_(eq))/(G-R_(eq)`
`therefore S=(500xx21)/(500-21)=10500/479`
`therefore S= 21.92 Omega`
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