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Question
The angles of a triangle are arranged in ascending order of magnitude. If the difference
between two consecutive angles is 10°, find the three angles.
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Solution
Given that,
The difference between two consecutive angles is `10^@`
Let x,x+10,x+20 be the consecutive angles differ by `10^@`
W.K.T sum of all angles of traingle is `180^@`
`x+x+10+x+20=180^@`
`3x+30=180^@`
⇒ `3x=180-30^@ ⇒ 3x=150^@`
⇒`x=50^@`
∴ `x=50^@`
∴ The required angles are
x,x+10 and x+20
x=50
x+10=50+10=60
x+20=50+10+10=70
The difference between two consecutive angles is `10^@` then three angles are ` 50^@,60^@ and 70^@`
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