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Question
State Charles's law.
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Solution
Charles's Law
At constant pressure, the volume of a given mass of a dry gas increases or decreases by 1/273rd of its original volume at 0°C for each degree centigrade rise or fall in temperature.
V ∝ T (at constant pressure)
At temperature T1 (K) and volume V1 (cm3):
`"V"_1 ∝ "T"_1 "or" "V"_1/"T"_1 = "K"` = constant...(i)
At temperature T2 (K) and volume V2 (cm3):
`"V"_2 ∝ "T"_2 "or" "V"_2/"T"_2 = "K"` = constant….(ii)
From (i) and (ii),
`"V"_1/"T"_1 = "V"_2/"T"_2` = constant
For Temperature = Conversion from Celsius to Kelvin
1 K = °C + 273
Example:
20°C = 20 + 273 = 293 K
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