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88 cm3 of nitrogen is at a pressure of 770 mm mercury. If the pressure is raised to 880 mmHg, find by how much the volume will diminish, temperature remaining constant.

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Question

88 cm3 of nitrogen is at a pressure of 770 mm mercury. If the pressure is raised to 880 mmHg, find by how much the volume will diminish, the temperature remaining constant.

Numerical
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Solution

V = 88 cm3 

P = 770 mm

P1 = 880 mm 

V1= ? 

T = T1

Using gas equation,

`"PV"/"T" = ("P"_1 "V"_1)/"T"_1`

`(770 xx 88)/"T" = (880 xx "V"_1)/"T"`

V1 = 77 cm3

Volume diminishes = 88 - 77 = 11 cm3  

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Fundamental Laws of Gases - Temperature - Volume Relationship or Charles's Law
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Chapter 7: Study of Gas Laws - Exercise 7 (B) [Page 126]

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Selina Concise Chemistry [English] Class 9 ICSE
Chapter 7 Study of Gas Laws
Exercise 7 (B) | Q 8 | Page 126
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